Drawing the Lewis Structures for OCS






Transcript: For the OCS Lewis structure, we have 6 valence electrons for Oxygen, plus 4 for Carbon, and 6 for Sulfur for a total of 16 valence electrons for the OCS Lewis structure. Carbon is the least electronegative. We'll put that in the center. We'll put the Oxygen on one side and Sulfur on the other. We have 16 valence electrons for the OCS Lewis structure. We'll put 2 between atoms to form chemical bonds; we've used four. Then we'll go around the outside to fill the octets on those atoms, or until we run out of valence electrons. Two, 4, 6, and 16 valence electrons.

So we've used all 16 valence electrons. The Sulfur and the Oxygen both have eight valence electrons, so their octets are full, but the Carbon in the center only has four valence electrons. Let's take two valence electrons here and share them with the Carbon to form a double bond. The Sulfur still has eight valence electrons, but now the Carbon has six valence electrons and we're still only using 16 valence electrons for the OCS Lewis structure. Let's take these two here and move them to the center, as well. Now the Oxygen has eight valence electrons; but the Carbon in the center also has eight valence electrons, so it has an octet. Again, we're still using only the 16 valence electrons available for the OCS Lewis structure.

So that is the Lewis structure for OCS. This is Dr. B., and thanks for watching.